https://atcoder.jp/contests/math-and-algorithm/tasks/math_and_algorithm_g
包除原理ですね。これを使うために最小公倍数が要ります。
// Number of Multiples 1 #![allow(non_snake_case)] //////////////////// library //////////////////// fn read<T: std::str::FromStr>() -> T { let mut line = String::new(); std::io::stdin().read_line(&mut line).ok(); line.trim().parse().ok().unwrap() } fn read_vec<T: std::str::FromStr>() -> Vec<T> { read::<String>().split_whitespace() .map(|e| e.parse().ok().unwrap()).collect() } fn gcd(n: i32, m: i32) -> i32 { if m == 0 { n } else { gcd(m, n % m) } } fn lcm(n: i32, m: i32) -> i32 { n / gcd(n, m) * m } //////////////////// process //////////////////// fn read_input() -> (i32, i32, i32) { let v = read_vec(); (v[0], v[1], v[2]) } fn f(N: i32, X: i32, Y: i32) -> i32 { let D = lcm(X, Y); N / X + N / Y - N / D } fn main() { let (N, X, Y) = read_input(); println!("{}", f(N, X, Y)) }